SimuVeda

Chemistry · Simulator 021

Reaction Rates

Particles of A and B collide and sometimes react to form C. Change the temperature, starting concentrations and activation energy, and compare the collision picture with the rate law and the Arrhenius equation.

How the model works

The model reaction is elementary and second order:

A + B → C, rate = k [A][B], k = A_f · e^(−Ea / RT)

Two things set the rate. Collision frequency grows with concentration (more particles per volume). The fraction of collisions with enough energy grows steeply with temperature: only collisions with energy above the activation energy Ea react, and the Boltzmann factor e^(−Ea/RT) gives that fraction.

The right-hand graph integrates the rate law exactly (it shows the expected concentrations). The particle box is a stochastic illustration with a fixed random seed, so Reset replays the same run. The rule of thumb that “every 10 °C doubles the rate” holds only for Ea ≈ 50 kJ/mol near room temperature.

Model reaction with a stated pre-exponential factor A_f = 1.0×10⁹ L/(mol·s). It is not a specific real reaction; real mechanisms can have several steps.

Guided experiments

  1. Heat it up by 10 °C. Ea = 50 kJ/mol, compare 298 K with 308 K. Prediction: k rises by a factor e^(Ea/R × (1/298 − 1/308)) ≈ 1.93, so the rate nearly doubles.
  2. Double [A]. Keep T fixed and double the starting [A]. Prediction: the initial rate doubles (first order in A). The reaction stops when B runs out, because B is now limiting.
  3. A catalyst. Lower Ea from 50 to 40 kJ/mol at 298 K. Prediction: k rises by e^(10000/(8.314 × 298)) ≈ 57 times, from a modest change in Ea.

Challenge

A reaction's rate triples when heated from 25 °C to 45 °C. Estimate its activation energy.

Reveal the explanation

ln 3 = (Ea/R)(1/298.15 − 1/318.15). That gives Ea = 8.314 × 1.0986 / 2.108×10⁻⁴ ≈ 43 kJ/mol. Set Ea = 43 kJ/mol and compare k at 298 K and 318 K in the readout.

References

  • OpenStax, Chemistry 2e, §12.3 “Rate Laws” and §12.5 “Collision Theory”.